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Question 1 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy A lamp emitting 3000 lumens falls uniformly on a surface of 10 m². The illumination is
Choose your answer for question 1 A. 0.0033 lux B. 30 lux C. 300 lux D. 3000 luxAnswer and explanation Correct answer: C
Illumination = flux / area = 3000/10 = 300 lux.
Question 2 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy The illumination at a point on a surface from a point source varies
Choose your answer for question 2 A. inversely as the square of the distance B. directly as the square of the distance C. directly as the distance D. inversely as the distanceAnswer and explanation Correct answer: A
E = I cos θ / d² is the inverse square law.
Question 3 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy Induction heating works on the principle of
Choose your answer for question 3 A. the passage of current through a resistive element B. dielectric loss in an insulator C. eddy currents induced in the workpiece D. arcing between electrodesAnswer and explanation Correct answer: C
An alternating magnetic field induces eddy currents in a conducting charge, which heat it.
Question 4 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy DC series motors are widely used in traction because they have
Choose your answer for question 4 A. a constant speed B. a high starting torque C. a low starting current D. a very high no-load speedAnswer and explanation Correct answer: B
The torque varies with the square of the current, so the series motor gives a large torque at low speed.
Question 5 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy A room of 10 m × 6 m must be lit to 300 lux. The utilisation factor is 0.5 and the maintenance factor is 0.8. The total luminous flux required is
Choose your answer for question 5 A. 22 500 lm B. 90 000 lm C. 18 000 lm D. 45 000 lmAnswer and explanation Correct answer: D
Flux = E A / (UF × MF) = 300 × 60 / (0.5 × 0.8) = 45 000 lm.
Question 6 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy A 10 kW heating element is designed to operate at 230 V. Its resistance is about
Choose your answer for question 6 A. 5.29 Ω B. 0.043 Ω C. 52.9 Ω D. 23 ΩAnswer and explanation Correct answer: A
R = V²/P = 230² / 10 000 = 5.29 Ω.
Question 7 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy Regenerative braking in electric traction
Choose your answer for question 7 A. is possible only in steam locomotives B. needs no electrical machine C. wastes the energy as heat in resistors D. returns the kinetic energy of the train to the supplyAnswer and explanation Correct answer: D
The traction motors act as generators during braking and feed power back to the overhead line.
Question 8 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy According to Faraday’s first law of electrolysis, the mass of a substance deposited is proportional to
Choose your answer for question 8 A. the square of the current B. the temperature of the electrolyte C. the voltage applied D. the quantity of charge passedAnswer and explanation Correct answer: D
m = Z Q, where Z is the electrochemical equivalent of the substance.
Question 9 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy A hall of 60 m² needs 500 lux. With a utilisation factor of 0.6 and a maintenance factor of 0.9, the total luminous flux required is about
Choose your answer for question 9 A. 16200 lumens B. 50000 lumens C. 55556 lumens D. 30000 lumensAnswer and explanation Correct answer: C
Flux = E A/(UF × MF) = 500 × 60 / (0.6 × 0.9) = 55556 lm.
Question 10 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy A hall of 100 m² needs 300 lux. With a utilisation factor of 0.5 and a maintenance factor of 0.7, the total luminous flux required is about
Choose your answer for question 10 A. 30000 lumens B. 60000 lumens C. 85714 lumens D. 10500 lumensAnswer and explanation Correct answer: C
Flux = E A/(UF × MF) = 300 × 100 / (0.5 × 0.7) = 85714 lm.
Question 11 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy A hall of 100 m² needs 200 lux. With a utilisation factor of 0.4 and a maintenance factor of 0.9, the total luminous flux required is about
Choose your answer for question 11 A. 20000 lumens B. 50000 lumens C. 7200 lumens D. 55556 lumensAnswer and explanation Correct answer: D
Flux = E A/(UF × MF) = 200 × 100 / (0.4 × 0.9) = 55556 lm.
Question 12 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy A 5 kW resistance heating element is designed for 230 V. Its resistance is about
Choose your answer for question 12 A. 21.16 Ω B. 0.046 Ω C. 10.58 Ω D. 21.739 ΩAnswer and explanation Correct answer: C
R = V²/P = 230² / 5000 = 10.58 Ω.
Question 13 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy In electrolytic deposition of copper (electrochemical equivalent Z = 0.00033 g/C), a current of 5 A flows for 3 hours. The mass deposited is about
Choose your answer for question 13 A. 0.3 g B. 17820 g C. 0 g D. 17.82 gAnswer and explanation Correct answer: D
m = Z I t = 0.00033 × 5 × 10800 s = 17.82 g.
Question 14 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy 20 kg of water is heated through 30 °C in an electric heater of efficiency 70 percent (cp = 4.18 kJ/kg·K). The electrical energy consumed is about
Choose your answer for question 14 A. 0.488 kWh B. 0.995 kWh C. 0.697 kWh D. 9.952 kWhAnswer and explanation Correct answer: B
Heat needed = 20 × 4.18 × 30 = 2508 kJ. Energy = 2508/0.7 = 3582.9 kJ = 0.995 kWh.
Question 15 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy 20 kg of water is heated through 20 °C in an electric heater of efficiency 85 percent (cp = 4.18 kJ/kg·K). The electrical energy consumed is about
Choose your answer for question 15 A. 0.546 kWh B. 5.464 kWh C. 0.464 kWh D. 0.395 kWhAnswer and explanation Correct answer: A
Heat needed = 20 × 4.18 × 20 = 1672 kJ. Energy = 1672/0.85 = 1967.1 kJ = 0.546 kWh.
Question 16 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy 100 kg of water is heated through 20 °C in an electric heater of efficiency 85 percent (cp = 4.18 kJ/kg·K). The electrical energy consumed is about
Choose your answer for question 16 A. 2.322 kWh B. 2.732 kWh C. 27.32 kWh D. 1.974 kWhAnswer and explanation Correct answer: B
Heat needed = 100 × 4.18 × 20 = 8360 kJ. Energy = 8360/0.85 = 9835.3 kJ = 2.732 kWh.
Question 17 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy A luminous flux of 8000 lumens falls uniformly on a surface of 10 m². The illumination is
Choose your answer for question 17 A. 80000 lux B. 800 lux C. 1200 lux D. 80 luxAnswer and explanation Correct answer: B
E = flux/area = 8000/10 = 800 lux.
Question 18 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy A hall of 100 m² needs 200 lux. With a utilisation factor of 0.4 and a maintenance factor of 0.7, the total luminous flux required is about
Choose your answer for question 18 A. 20000 lumens B. 50000 lumens C. 5600 lumens D. 71429 lumensAnswer and explanation Correct answer: D
Flux = E A/(UF × MF) = 200 × 100 / (0.4 × 0.7) = 71429 lm.
Question 19 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy A hall of 20 m² needs 100 lux. With a utilisation factor of 0.5 and a maintenance factor of 0.7, the total luminous flux required is about
Choose your answer for question 19 A. 700 lumens B. 4000 lumens C. 2000 lumens D. 5714 lumensAnswer and explanation Correct answer: D
Flux = E A/(UF × MF) = 100 × 20 / (0.5 × 0.7) = 5714 lm.
Question 20 · Electrical Engineering (SSC JE) · Utilization of Electrical Energy A 6 V battery has a capacity of 60 Ah. The energy it can store is
Choose your answer for question 20 A. 0.36 kWh B. 10 kWh C. 0.072 kWh D. 360 kWhAnswer and explanation Correct answer: A
Energy = V × Ah = 6 × 60 = 360 Wh = 0.36 kWh.