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English SSC CGL Tier I papers. Free 60-minute mocks, 100 questions, 200 marks; +2 correct and −0.5 incorrect. Source: SSC response sheets preserved by SSC Portal. The marked archived keys have not been independently revalidated against final SSC keys; worked explanations are pending review. A/B/C/D correspond to source options 1/2/3/4.

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Question 1 · Mechanical Engineering (SSC JE) · Engineering Mechanics
The angle of friction is equal to
Choose your answer for question 1
Answer and explanation

Correct answer: C

tan φ = μ, and the angle of repose, at which a body is just about to slide, has the same value.

Question 2 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A body of mass 2 kg moves at 4 m/s. Its kinetic energy is
Choose your answer for question 2
Answer and explanation

Correct answer: C

KE = ½mv² = 0.5 × 2 × 16 = 16 J.

Question 3 · Mechanical Engineering (SSC JE) · Engineering Mechanics
The centre of gravity of a triangle from its base is at a distance of
Choose your answer for question 3
Answer and explanation

Correct answer: B

The centroid lies at the intersection of the medians, at h/3 from the base.

Question 4 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A projectile has the maximum horizontal range on level ground when its angle of projection is
Choose your answer for question 4
Answer and explanation

Correct answer: B

R = u² sin 2θ / g is largest when sin 2θ = 1, that is, θ = 45°.

Question 5 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A block of mass 20 kg rests on a horizontal floor with μ = 0.3 (g = 9.81 m/s²). The friction force that must be overcome to start the block sliding is
Choose your answer for question 5
Answer and explanation

Correct answer: A

F = μ m g = 0.3 × 20 × 9.81 = 58.9 N.

Question 6 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A ball of mass 0.5 kg moving at 10 m/s bounces back with the same speed from a wall. The magnitude of the impulse is
Choose your answer for question 6
Answer and explanation

Correct answer: A

Impulse = change in momentum = 0.5 × 10 − (−0.5 × 10) = 10 N·s.

Question 7 · Mechanical Engineering (SSC JE) · Engineering Mechanics
The moment of inertia of a uniform solid disc of mass m and radius r about an axis through its centre and perpendicular to its plane is
Choose your answer for question 7
Answer and explanation

Correct answer: B

I = ½ m r² for a solid disc, m r² for a thin ring and ⅖ m r² for a solid sphere.

Question 8 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A mass of 1 kg is attached to a spring of stiffness 100 N/m. The time period of vibration is about
Choose your answer for question 8
Answer and explanation

Correct answer: B

T = 2π √(m/k) = 2π √(1/100) = 0.628 s.

Question 9 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A body of mass 5 kg moves with a velocity of 2 m/s. Its kinetic energy is
Choose your answer for question 9
Answer and explanation

Correct answer: A

KE = ½mv² = 0.5 × 5 × 2² = 10 J.

Question 10 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A block weighing 40 N rests on a horizontal surface with a coefficient of friction 0.2. The horizontal force needed to just move it is
Choose your answer for question 10
Answer and explanation

Correct answer: D

F = μN = 0.2 × 40 = 8 N.

Question 11 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A mass of 2 kg is raised through a height of 5 m (g = 9.81 m/s²). The increase in potential energy is
Choose your answer for question 11
Answer and explanation

Correct answer: D

PE = mgh = 2 × 9.81 × 5 = 98.1 J.

Question 12 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A projectile is fired at 30 m/s at 75° to the horizontal (g = 9.81 m/s²). The horizontal range is about
Choose your answer for question 12
Answer and explanation

Correct answer: D

R = u² sin2θ/g = 30² × sin 150° / 9.81 = 45.87 m.

Question 13 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A body of mass 1 kg moving at 10 m/s collides with a body of mass 1 kg moving at 3 m/s in the same direction, and they stick together. The common velocity is
Choose your answer for question 13
Answer and explanation

Correct answer: B

v = (m1u1 + m2u2)/(m1 + m2) = (10 + 3)/2 = 6.5 m/s.

Question 14 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A body of mass 2 kg moving at 10 m/s collides with a body of mass 2 kg moving at 2 m/s in the same direction, and they stick together. The common velocity is
Choose your answer for question 14
Answer and explanation

Correct answer: B

v = (m1u1 + m2u2)/(m1 + m2) = (20 + 4)/4 = 6 m/s.

Question 15 · Mechanical Engineering (SSC JE) · Engineering Mechanics
The coefficient of friction between a block and an inclined plane is 0.13. The angle of repose (angle of friction) is about
Choose your answer for question 15
Answer and explanation

Correct answer: C

tanφ = μ, so φ = tan⁻¹(0.13) = 7.4°.

Question 16 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A body of mass 1 kg moving at 10 m/s collides with a body of mass 1 kg moving at 1 m/s in the same direction, and they stick together. The common velocity is
Choose your answer for question 16
Answer and explanation

Correct answer: C

v = (m1u1 + m2u2)/(m1 + m2) = (10 + 1)/2 = 5.5 m/s.

Question 17 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A projectile is fired at 40 m/s at 30° to the horizontal (g = 9.81 m/s²). The time of flight is about
Choose your answer for question 17
Answer and explanation

Correct answer: C

T = 2u sinθ/g = 4.08 s.

Question 18 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A projectile is fired at 10 m/s at 75° to the horizontal (g = 9.81 m/s²). The horizontal range is about
Choose your answer for question 18
Answer and explanation

Correct answer: B

R = u² sin2θ/g = 10² × sin 150° / 9.81 = 5.1 m.

Question 19 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A block weighing 40 N rests on a horizontal surface with a coefficient of friction 0.35. The horizontal force needed to just move it is
Choose your answer for question 19
Answer and explanation

Correct answer: D

F = μN = 0.35 × 40 = 14 N.

Question 20 · Mechanical Engineering (SSC JE) · Engineering Mechanics
A mass of 10 kg is raised through a height of 10 m (g = 9.81 m/s²). The increase in potential energy is
Choose your answer for question 20
Answer and explanation

Correct answer: C

PE = mgh = 10 × 9.81 × 10 = 981 J.

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