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English SSC CGL Tier I papers. Free 60-minute mocks, 100 questions, 200 marks; +2 correct and −0.5 incorrect. Source: SSC response sheets preserved by SSC Portal. The marked archived keys have not been independently revalidated against final SSC keys; worked explanations are pending review. A/B/C/D correspond to source options 1/2/3/4.

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Civil Engineering (SSC JE)

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Question 1 · Civil Engineering (SSC JE) · Surveying
A 20 m metric chain has how many links?
Choose your answer for question 1
Answer and explanation

Correct answer: C

Each link of a metric chain is 0.2 m, so a 20 m chain has 100 links (a 30 m chain has 150).

Question 2 · Civil Engineering (SSC JE) · Surveying
A line has a reduced bearing of S 40° W. Its whole circle bearing is
Choose your answer for question 2
Answer and explanation

Correct answer: B

In the south-west quadrant, WCB = 180° + reduced bearing = 180° + 40° = 220°.

Question 3 · Civil Engineering (SSC JE) · Surveying
Contours of different elevations can meet or cross each other only in the case of
Choose your answer for question 3
Answer and explanation

Correct answer: C

On a vertical cliff several contours coincide, and on an overhanging cliff they appear to cross. Elsewhere, contours of different levels never meet.

Question 4 · Civil Engineering (SSC JE) · Surveying
In levelling, the backsight reading on a benchmark of RL 100.000 m is 1.500 m and the foresight reading on a point P is 2.300 m. The RL of P is
Choose your answer for question 4
Answer and explanation

Correct answer: B

HI = 100.000 + 1.500 = 101.500 m. RL of P = HI − FS = 101.500 − 2.300 = 99.200 m.

Question 5 · Civil Engineering (SSC JE) · Surveying
Taking observations on both faces of a theodolite eliminates
Choose your answer for question 5
Answer and explanation

Correct answer: B

Face left and face right readings are averaged, so errors from the line of collimation, horizontal axis and vertical circle index cancel out.

Question 6 · Civil Engineering (SSC JE) · Surveying
The arithmetic check in levelling is that ΣBS − ΣFS equals
Choose your answer for question 6
Answer and explanation

Correct answer: B

Both the HI method and the rise and fall method must satisfy ΣBS − ΣFS = Σrise − Σfall = last RL − first RL.

Question 7 · Civil Engineering (SSC JE) · Surveying
In stadia tacheometry with a horizontal line of sight, the horizontal distance is D = Ks + C. The multiplying constant K is usually
Choose your answer for question 7
Answer and explanation

Correct answer: B

In an external focusing instrument K is normally 100 and the additive constant C is about 0.3 m. In an internal focusing instrument C is almost zero.

Question 8 · Civil Engineering (SSC JE) · Surveying
The magnetic bearing of a line is 78° and the magnetic declination is 3° east. The true bearing is
Choose your answer for question 8
Answer and explanation

Correct answer: B

True bearing = magnetic bearing + declination (east is positive) = 78° + 3° = 81°.

Question 9 · Civil Engineering (SSC JE) · Surveying
According to the Bowditch rule, the correction applied to the latitude or departure of a traverse side is proportional to
Choose your answer for question 9
Answer and explanation

Correct answer: A

The rule distributes the closing error in proportion to the length of each line, which suits cases where angles and distances are equally precise.

Question 10 · Civil Engineering (SSC JE) · Surveying
The combined correction for the curvature of the earth and refraction over a sight of 2 km is about (use 0.0673 D², with D in km)
Choose your answer for question 10
Answer and explanation

Correct answer: C

Combined correction = 0.0673 D² = 0.0673 × 4 = 0.269 m. The curvature correction alone is 0.0785 D².

Question 11 · Civil Engineering (SSC JE) · Surveying
A simple circular curve has radius 300 m and deflection angle 60°. The tangent length is
Choose your answer for question 11
Answer and explanation

Correct answer: A

T = R tan(Δ/2) = 300 × tan 30° = 300 × 0.5774 = 173.2 m.

Question 12 · Civil Engineering (SSC JE) · Surveying
Contours are drawn at a 5 m interval. Two successive contours are 100 m apart horizontally. The gradient of the ground is
Choose your answer for question 12
Answer and explanation

Correct answer: D

Gradient = vertical interval / horizontal distance = 5 / 100 = 1 in 20.

Question 13 · Civil Engineering (SSC JE) · Surveying
The minimum number of satellites needed to fix a three-dimensional position with a GPS receiver is
Choose your answer for question 13
Answer and explanation

Correct answer: B

Three satellites give three distances, and a fourth is required to solve for the receiver clock error.

Question 14 · Civil Engineering (SSC JE) · Surveying
A vertical aerial photograph is taken with a camera of focal length 150 mm from a height of 3000 m above flat ground. The scale of the photograph is
Choose your answer for question 14
Answer and explanation

Correct answer: B

Scale = f / H = 0.15 / 3000 = 1 / 20 000.

Question 15 · Civil Engineering (SSC JE) · Surveying
The fore bearing of a line AB is 248°. The back bearing of the line is
Choose your answer for question 15
Answer and explanation

Correct answer: A

Back bearing = fore bearing − 180° = 68°.

Question 16 · Civil Engineering (SSC JE) · Surveying
A level is set up between a benchmark of RL 105 m and a point P. The backsight on the benchmark is 1.5 m and the foresight on P is 1.8 m. The RL of P is
Choose your answer for question 16
Answer and explanation

Correct answer: A

RL of P = RL of BM + BS − FS = 105 + 1.5 − 1.8 = 104.700 m.

Question 17 · Civil Engineering (SSC JE) · Surveying
The fore bearing of a line AB is 75°. The back bearing of the line is
Choose your answer for question 17
Answer and explanation

Correct answer: B

Back bearing = fore bearing + 180° = 255°.

Question 18 · Civil Engineering (SSC JE) · Surveying
Contours are drawn at an interval of 1 m. Two successive contours are 150 m apart horizontally. The ground slope is 1 in
Choose your answer for question 18
Answer and explanation

Correct answer: C

Gradient = vertical interval / horizontal distance = 1/150, that is 1 in 150.

Question 19 · Civil Engineering (SSC JE) · Surveying
The whole circle bearing of a line is 81°. Its reduced bearing is
Choose your answer for question 19
Answer and explanation

Correct answer: A

In the NE quadrant, RB = WCB, so RB = N 81° E.

Question 20 · Civil Engineering (SSC JE) · Surveying
A level is set up between a benchmark of RL 100.5 m and a point P. The backsight on the benchmark is 1.5 m and the foresight on P is 1.1 m. The RL of P is
Choose your answer for question 20
Answer and explanation

Correct answer: C

RL of P = RL of BM + BS − FS = 100.5 + 1.5 − 1.1 = 100.900 m.

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