SSC CGL Tier I - 09 September 2024 - Shift 1
100 questions · 60 minutes · 4 subjects
SSC · Steel Structures practice
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English SSC CGL Tier I papers. Free 60-minute mocks, 100 questions, 200 marks; +2 correct and −0.5 incorrect. Source: SSC response sheets preserved by SSC Portal. The marked archived keys have not been independently revalidated against final SSC keys; worked explanations are pending review. A/B/C/D correspond to source options 1/2/3/4.
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As per IS 800:2007, the minimum pitch of bolts should be
Answer and explanation
Correct answer: D
IS 800:2007 gives a minimum pitch of 2.5d to avoid bearing failure between adjacent holes and to allow space for tightening.
A bolt that transfers load by friction between the connected plates is called
Answer and explanation
Correct answer: A
HSFG bolts are tightened to a high pretension so that the clamped plates carry the load by friction rather than by bolt shear.
The theoretical effective length of a column fixed at both ends is
Answer and explanation
Correct answer: D
The theoretical values are 0.5L for fixed-fixed, 0.7L for fixed-hinged, L for hinged-hinged and 2L for fixed-free. IS 800 recommends 0.65L for design.
The slenderness ratio of a steel column is the ratio of
Answer and explanation
Correct answer: B
Slenderness ratio λ = Le / r_min and it decides the buckling strength of a compression member.
The yield stress of structural steel of grade E250 as per IS 2062 is
Answer and explanation
Correct answer: A
The grade number E250 is the minimum yield strength in MPa. The ultimate tensile strength of this steel is 410 MPa.
For an equal-leg fillet weld of size s with a 90° angle between fusion faces, the effective throat thickness is
Answer and explanation
Correct answer: A
The throat is the shortest distance from the root to the face of the weld triangle, which equals s cos 45° = 0.707 s.
As per IS 800:2007, the minimum effective length of a fillet weld should not be less than
Answer and explanation
Correct answer: A
Shorter welds are not allowed because the end craters make them unreliable. The minimum is 4 times the weld size.
Bearing stiffeners in a plate girder are provided
Answer and explanation
Correct answer: C
They prevent crippling or buckling of the web under local loads and reactions.
A plate 200 mm wide and 10 mm thick has two bolt holes of 20 mm diameter in the same cross-section. The net sectional area is
Answer and explanation
Correct answer: A
Anet = (b − n dh) t = (200 − 2 × 20) × 10 = 1600 mm².
Purlins in a roof truss are designed mainly for
Answer and explanation
Correct answer: C
Purlins span between trusses and carry the roof sheeting loads, so they act as beams, often bending about both axes on a sloping roof.
A flat 250 mm wide and 8 mm thick has 3 bolt holes of 14 mm diameter in one cross-section. The net sectional area is
Answer and explanation
Correct answer: B
Anet = (b − n dh) t = (250 − 3 × 14) × 8 = 1664 mm².
A column of length 6 m is hinged at both ends, with an effective length factor of 1. If its minimum radius of gyration is 25 mm, the slenderness ratio is
Answer and explanation
Correct answer: B
λ = KL/r = 1 × 6000 / 25 = 240.
In working stress design, the permissible stress for bending in tension or compression is 0.66 fy. For a steel with fy = 300 MPa, it is
Answer and explanation
Correct answer: B
0.66 × 300 = 198 MPa.
A flat 200 mm wide and 8 mm thick has 2 bolt holes of 18 mm diameter in one cross-section. The net sectional area is
Answer and explanation
Correct answer: B
Anet = (b − n dh) t = (200 − 2 × 18) × 8 = 1312 mm².
A steel beam of span 5.8 m is required not to deflect by more than span/500 under service loads. The maximum permissible deflection is
Answer and explanation
Correct answer: B
δmax = span/500 = 5800/500 = 11.6 mm.
A 12 mm diameter bolt of grade 4.6 (fub = 400 MPa) is in tension. Taking the net tensile area as 0.78 of the shank area and γmb = 1.25, the design tension capacity Tnb = 0.9 fub An/γmb is about
Answer and explanation
Correct answer: B
An = 0.78 × π × 12²/4 = 88.2 mm². Tnb = 0.9 × 400 × 88.2 / 1.25 = 25406 N = 25.4 kN.
The gross area of a tension member is 1500 mm² and the steel has a yield stress of 300 MPa. Its design strength governed by gross section yielding, Tdg = Ag fy/γm0 with γm0 = 1.10, is about
Answer and explanation
Correct answer: C
Tdg = 1500 × 300 / 1.10 = 409000 N = 409 kN.
A 20 mm diameter bolt of grade 4.6 (fub = 400 MPa) is in tension. Taking the net tensile area as 0.78 of the shank area and γmb = 1.25, the design tension capacity Tnb = 0.9 fub An/γmb is about
Answer and explanation
Correct answer: A
An = 0.78 × π × 20²/4 = 245 mm². Tnb = 0.9 × 400 × 245 / 1.25 = 70573 N = 70.6 kN.
A 20 mm diameter bolt of grade 8.8 (fub = 800 MPa) is in tension. Taking the net tensile area as 0.78 of the shank area and γmb = 1.25, the design tension capacity Tnb = 0.9 fub An/γmb is about
Answer and explanation
Correct answer: C
An = 0.78 × π × 20²/4 = 245 mm². Tnb = 0.9 × 800 × 245 / 1.25 = 141145 N = 141.1 kN.
A steel column has a least moment of inertia of 500 cm⁴ and a length of 4 m with an effective length factor 0.65. Taking E = 2 × 10⁵ MPa, the Euler buckling load is about
Answer and explanation
Correct answer: B
Le = 0.65 × 4 = 2.6 m. Pcr = π²EI/Le² = π² × 2×10⁵ × 500×10⁴ / (2600)² = 1460 kN.
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